58*10^2x=87

Solution for 58*10^2x=87 equation:

58*10^2x=87

We move all terms to the left:

58*10^2x-(87)=0

Wy multiply elements

580x^2-87=0

a = 580; b = 0; c = -87;
Δ = b2-4ac
Δ = 02-4·580·(-87)
Δ = 201840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{201840}=\sqrt{13456*15}=\sqrt{13456}*\sqrt{15}=116\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-116\sqrt{15}}{2*580}=\frac{0-116\sqrt{15}}{1160}
=-\frac{116\sqrt{15}}{1160}
=-\frac{\sqrt{15}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+116\sqrt{15}}{2*580}=\frac{0+116\sqrt{15}}{1160}
=\frac{116\sqrt{15}}{1160}
=\frac{\sqrt{15}}{10}
$